Question

0.5 mole of diatomic gas at ${27}^{0}C$ is heated at constant pressure so that its volume is trebled. If $R=8.3Jmol{e}^{-1}{k}^{-1}$ then work done is

• A. 4980 J
• B. 2490 J
• C. 630 J
• D. 1245 J

Answer 1

The correct option is B 2490 J

$\text{Given}:$n = 0.5, T = ${27}^{o}C$, R = 8.3 J/mole/k

$\text{Solution}:$

Work done = $p(V_f-V_i)$

= $p(3V_i-V_i)$

= $2p{V}_i$ (Since PV = nRT)

Thus,

$W=2\times n\times R\times T$

=$2\times 0.5\times 8.3\times 300=2.49KJ=2490J$

$\text{Hence B is the correct option}$