0.5 moles of gas A and x moles of gas B exert a pressure of 200Pa in a container of volume 10m3 at 1000K.
Given R is the gas constant in JK−1mol−1, x is:
A
2R4+12
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B
2R4−R
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C
4−R2R
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D
4+R2R
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Solution
The correct option is C4−R2R Total mole, nT=(0.5+x)
Ideal gas equation, PV=nRT 200×10=(0.5+x)×R×1000 2=(0.5+x)R 2R=12+x 4R−1=2x 4−R2R=x
or, x=4−R2R