Question

0.5 moles of n-hexane was treated with 9 moles of oxygen. Calculate the mass of carbon dioixde formed.

• A. 100 g
• B. 132 g
• C. 106 g
• D. 130 g

Answer 1

The correct option is B 132 g

$C_6{H}_{12\left(l\right)}+9O_{2\left(g\right)}\to 6C{O}_2+6H_2{O}_{\left(g\right)}$
From the stoichiometry,
1 moles of hexane react with 9 moles of oxygen.
0.5 moles of hexane can react with 4.5 moles of oxygen.
Hence, hexane is the limiting agent.
Moles of carbondioxide = $6\times \text{moles of hexane}$ = 3
Mass of carbondioxide = $3\times 44$ = 132 g