Question

0.52 g of a dibasic acid required 100 mL of 0.2 N NaOH for complete neutralization.
The equivalent weight of acid is:

• A. 26
• B. 52
• C. 104
• D. 156

Answer 1

The correct option is A 26

Using ,
Equivalents of Acid = Equivalents of $NaOH$

$\frac{\text{Weight}}{\text{Equivalent weight}}\text{of acid}=N\times V\text{of}\left(NaOH\right)$

putting values,
$\frac{0.52}{\text{Equivalent weight}}=\frac{100\times 0.2}{1000}$

$\therefore \text{Equivalent weight}\text{of acid}=26$

Hence (a) is the correct answer.