0-56 g of a tribasic acid is completely neutralised with 100 mL M10 CaOH2- The molar mass of the acid is

Milliequivalents of acid = milliequivalent of Ca(OH)_2 nbsp; ∴0.56E× 1000 = 100 ×210 where, E = Equivalent mass ∴ E = 0.56 × 1000 × 102 × 100 = 28 g Given, a ...

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Standard XII

Chemistry

Equivalent Mass

0.56 g of a t...

Question

$0.56 g$ of a tribasic acid is completely neutralised with $100 mL$ $\frac{M}{10} C a (O H)_{2} .$ The molar mass of the acid is

56 g

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28 g

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112 g

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84 g

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Solution

The correct option is D $84 g$
$Milliequivalents of acid = milliequivalent of C a (O H)_{2}$
$∴ \frac{0.56}{E} \times 1000 = 100 \times \frac{2}{10}$
$where, E = Equivalent mass$
$∴ E = \frac{0.56 \times 1000 \times 10}{2 \times 100} = 28 g$
$Given, acid is tribasic.$
$So, molecular weight= 28 \times 3 = 84 g$
$Hence, molar mass of the acid = 84 g$

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0.56 g of a tribasic acid is completely neutralised with 100 mL M10 Ca(OH)2. The molar mass of the acid is

The correct option is D 84 gMilliequivalents of acid = milliequivalent of Ca(OH)2 ∴0.56E×1000=100×210 where, E = Equivalent mass ∴E=0.56×1000×102×100=28 g Given, acid is tribasic. So, molecular weight= 28×3=84 g Hence, molar mass of the acid=84 g

$0.56 g$ of a tribasic acid is completely neutralised with $100 mL$ $\frac{M}{10} C a (O H)_{2} .$ The molar mass of the acid is