0.5g of an organic compound on Kjeldahl’s analysis gave enough ammonia to just neutralise $10 c m^{3}$ of 1M $H_{2} S O_{4}$ . The $%$ of N in the compound is

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Solution

The correct option is A 56
$% o f N = \frac{1.4 \times molarity of acid \times basicity of acid \times volume of acid}{Mass of compound} = \frac{1.4 \times 1 \times 2 \times 10}{0.5} = 56$

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0.5g of an organic compound on kjeldhal's analysis gave enough ammonia to just neutralize 10cm3 of 1M $H_{2} S O_{4}$ . The $%$ of nitrogen in the compound is

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0.5g of an organic compound on Kjeldahl’s analysis gave enough ammonia to just neutralise 10cm3 of 1M H2SO4. The % of N in the compound is

The correct option is A 56% of N=1.4×molarity of acid×basicity of acid× volume of acidMass of compound=1.4×1×2×100.5=56

0.5g of an organic compound on Kjeldahl’s analysis gave enough ammonia to just neutralise $10 c m^{3}$ of 1M $H_{2} S O_{4}$ . The $%$ of N in the compound is

The correct option is A 56
$% o f N = \frac{1.4 \times molarity of acid \times basicity of acid \times volume of acid}{Mass of compound} = \frac{1.4 \times 1 \times 2 \times 10}{0.5} = 56$