Question

$0.6\text{X}+\frac{27}{3}\text{x}=\frac{34}{5}\text{X}-\frac{20.4}{6}\text{x}$. Here, if $\text{x}$ is 12, then the value of $\text{X}$ is .

• A. 12
• B. 24
• C. 18
• D. 2

Answer 1

The correct option is B 24

Given expression,
$0.6\text{X}+\frac{27}{3}\text{x}=\frac{34}{5}\text{X}-\frac{20.4}{6}\text{x}$

$⟹\frac{27}{3}\text{x}+\frac{20.4}{6}\text{x}=\frac{34}{5}\text{X}-0.6\text{X}$

$⟹\text{9x}+\text{3.4x}=\text{6.8X}-0.6\text{X}$

$⟹\text{12.4x}=\text{6.2X}$

Dividing with 6.2 on both sides

$⟹\frac{\text{12.4x}}{\text{6.2}}=\frac{\text{6.2X}}{6.2}$

$⟹\text{2x = X}$

$⟹2\times 12=\text{X}(\because \text{x}=12)$

$⟹\text{X}=24$