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Question

0.607g of the silver salt of a tribasic acid on combustion deposited 0.37g of pure silver. Calculate the molecular weight of the acid.
Enter the nearest integer value.

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Solution

Formula of silver salt =Ag3A(A is trivalent anion)

Ag3A3Ag
0.607g 0.37g

3×moles ofAg3A= moles of Ag

3×0.607Mol.wt.Ag3A=0.37108

Mol. wt Ag3A=3×0.607×1080.37=531.54

Wt. of A3=531.543×108=531.543204=207.54

Mol. formula of acid =H3A

Mol. wt =3×1+207.54=210.54g211 g

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