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Byju's Answer
Standard X
Chemistry
Mole Concept
0.607 g of th...
Question
0.607
g
of the silver salt of a tribasic acid on combustion deposited
0.37
g
of pure silver. Calculate the molecular weight of the acid.
Enter the nearest integer value.
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Solution
Formula of silver salt
=
A
g
3
A
(A is trivalent anion)
A
g
3
A
→
3
A
g
0.607
g
0.37
g
3
×
moles of
A
g
3
A
=
moles of
A
g
3
×
0.607
M
o
l
.
w
t
.
A
g
3
A
=
0.37
108
Mol. wt
A
g
3
A
=
3
×
0.607
×
108
0.37
=
531.54
Wt. of
A
3
−
=
531.54
−
3
×
108
=
531.54
−
3204
=
207.54
Mol. formula of acid
=
H
3
A
Mol. wt
=
3
×
1
+
207.54
=
210.54
g
≈
211
g
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