The correct option is C 4 J
The molecular weight of oxygen M=32 g/mol
number of moles of the gas,
n=0.64 g32 g.mol−1=0.02 mol
ΔT=35−25=10∘C=10 K
since difference of temperature in celcius and kelvin yields same result.
⇒The amount of heat (Q) is required at constant volume (because container's volume is fixed).
⇒Q=nCVΔT
Q=0.02 mol×20 JK−1mol−1×10 K
∴Q=4 J