$(0.7)^{2} - (0.3)^{2}$

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Solution

$(0.7)^{2} - (0.3)^{2} = (0.7 + 0.3) (0.7 - 0.3) = 1 \times 0.4 = 0.4$

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Similar questions

Q. Factorise:

(0.7)^{2} - (0.3)^{2}

Q. The difference

(0.7)^{2} - (0.3)^{2}

simplifies to

Q. Factorise by using formula:

(0.7)^{2} - (0.3)^{2}

is 0.4
If true then enter

1

and if false then enter

0

Factorise:

(i) $4 a^{2} - 25$ (ii) $x^{2} - \frac{9}{16}$ (iii) $x^{4} - y^{4}$ (iv) $[7 \frac{3}{10}]^{2} - [2 \frac{1}{10}]^{2}$ (v) $(0.7)^{2} - (0.3)^{2}$ (vi) $(5 a - 2 b)^{2} - (2 a - b)^{2}$

Q. In the reaction

4 A + 2 B + 3 C \to A_{4} B_{2} C_{3}

The number of moles of product formed, starting from one mole of A, 0.6 mole of B and 0.72 mole of C?

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(0.7)2−(0.3)2

(0.7)2−(0.3)2=(0.7+0.3)(0.7−0.3)=1×0.4=0.4

$(0.7)^{2} - (0.3)^{2}$

$(0.7)^{2} - (0.3)^{2} = (0.7 + 0.3) (0.7 - 0.3) = 1 \times 0.4 = 0.4$