Question

0.76 g of a silver salt of a dibasic acid was ignited. It gave 0.54 g of pure silver. The molecular mass of the acid is .

Answer 1

Mass of the silver salt taken = 0.76 g
Mass of silver left = 0.54 g
Basicity of the acid = 2

We know that,

$\frac{Weightofsilversalt}{Eqivalentweightofsilversalt}=\frac{Weightofsilver}{Eqivalentweightofsilver}$

$\frac{0.76}{E+107}=\frac{0.54}{108}$

Solving for E, we get E = 45

Since the acid is dibasic,

$Mw=Ew\times basicity$

$Mw=45\times 2$

$Mw=90g$