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Question

0.804 g sample of iron ore was dissolved in acid. Iron was oxidised to +2 state and it required 47.2 mL of 0.112NKMnO4 solution for titration. Calculate % of Fe3O4 in ore (as nearest integer).

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Solution

The redox changes are as follows:
FeFe2++2e
Fe2+Fe3++e
5e+Mn7+Mn2+
Meq. of Fe2+ = Meq. of KMnO4
w(561)×=47.2×0.112
wFe2+=0.296g
Purity of Fe=0.296×1000.804=36.82%
Now, Fe3O43Fe
3×56gFe obtained by 232gFe3O4
0.296gFe is obtained by 232×0.29656×3=0.409gFe3O4
% of Fe3O4=0.4090.804×100=50.84%
So, nearest integer value is 51.

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