Question

$0.84g$ of a metal carbonate reacts exactly with $40ml$ of $N/2H_{2}S{O}_4$. The equivalent weight of the metal carbonate is:

• A. $84$
• B. $64$
• C. $42$
• D. $32$

Answer 1

Answer: (C)

$42$

Let the equivalent weight of metal carbonate is $W$.

Number of equivalents metal carbonate $=\frac{0.84}{W}$

Comparing equivalents of metal carbonate and $H_{2}S{O}_4-$

$\frac{0.84}{W}=\frac{40\times 0.5}{1000}$

$W=42$

Hence, option $C$ is correct.