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Question

0.9 gm of a volatile solid organic compound (molecular weight=90), containing carbon, hydrogen and oxygen, was heated with 224 ml oxygen at 1 atm and 273 K. After combustion, the total volume of gases was 560 ml at 1 atm and 273 K. On treatment with KOH, the volume decreased to 112 ml. The formula of the organic compound is CxHyOz. Find (x+y+z)/2.

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Solution

CxHyOz+(2x+0.5yz)2O2xCO2+y2H2O
The number of moles of hydrocarbon =0.990=0.01
The number of moles of carbon dioxide =44822400=0.02
Hence, x=0.020.01=2
Total volume after combustion is 560 ml.
Total number of moles after combustion =56022400=0.025
The increase in the number of moles =0.0250.02=0.005. It is equal to z310
Hence, z=3
Hence, x+y+z=18

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