Question

$0.90gm$ of the acid (molecular weight $90gm$) is neutralized by $40mL$ of $0.5NNaOH$. What is the basicity of the acid?

• A. $1$
• B. $2$
• C. $3$
• D. $4$

Answer 1

Answer: (B)

$2$

Let the unknown acid be $H_{x}A$

Equating the number of moles of acid & base,

$\Rightarrow \frac{0.90}{90}\times x=40\times 0.5\times {10}^{-3}$

$\Rightarrow x=2$

Hence, basicity of the acid= $2$ .