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Question

02ex dx

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Solution

abfxdx=limh0 hfa+fa+h+fa+2h...............+fa+n-1hwhere h=b-an

Here a=0, b=2, fx=ex, h=2-0n=2nTherefore,I=02exdx=limh0 hf0+f0+h+....................+f0+n-1h=limh0 he0+eh+e2h+.......+en-1h=limh0 hehn-1eh-1=limh0 e2-1eh-1h=e2-11=e2-1

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