Question

1.0 g of a metal combines with 8.89 g of Bromine. Equivalent weight of metal is nearly :

• A. 8
• B. 9
• C. 10
• D. 7

Answer 1

Answer: (B)

9

The equivalent mass of the metal is the number of parts by mass of metal that combines with 79.9 parts by mass of bromine.
1.0 g of metal combines with 8.89 g of bromine.
Hence, the mass of metal that combines with 79.9 g of bromine is $\frac{79.9}{8.89}\times 1=9$ g.
Hence, the equivalent weight of metal is 9.