You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Chemistry

The Ideal Gas Equation

1.0 kg of wat...

Question

1.0 kg of water is contained in a 1.25 kW kettle. Calculate the time taken for the temperature of water to rise from $25^{\circ} C$ to its boiling point $100^{\circ} C$ . Specific heat capacity of water = $4.2 J g^{- 1} K^{- 1}$ .

Open in App

Solution

Let the time taken is t
Heat loss by kettle=heat gain water
$1.25 \times 10^{3} \times t = Q = m C Δ T$
C is the specific heat capacity of water
eg: C= $42$ J/kg/k
$Δ T = (100 - 25) ℃$
$1250 \times t = 1 \times 4200 \times (100 - 25) 1250 \times t = 4200 \times 75 50 t = 12600 t = \frac{1260}{5} = 252$ sec

Suggest Corrections

Similar questions

1.0 k g

of water is contained in a

1.25 k W

kettle. Calculate the time taken for the temperature of water rise from

25^{o} C

to its boiling point

100^{o} C

. Specific heat capacity of water

= 4.2 J g^{- 1} K^{- 1}

Q. 200 g of hot water at

80^{0}

C is added to 300 g of cold water at

10^{0}

C. Neglecting the heat taken by the container, calculate the final temperature of the mixture of water . Specific heat capacity of water = 4200 J

k g^{- 1} K^{- 1}

Q. Calculate the total amount of heat energy required to convert

100 g

of ice at

- 10^{\circ} C

completely into water at

100^{\circ} C

. Specific heat capacity of ice =

2.1 J g^{- 1} K^{- 1}

, specific heat capacity of water =

4.2 J g^{- 1} K^{- 1}

, specific latent heat of ice =

336 J g^{- 1}

Q. A sphere of aluminium of mass 0.047 kg placed for sufficient time in a vessel containing boiling water, so that the sphere is at

100^{\circ} C

.It is then immediately transferred to 0.14 kg copper calorimeter containing 0.25 kg of water at

20^{\circ} C

. The temperature of water rises and attains a steady state at

23^{\circ} C

.Calculate the specific h capacity of aluminium. Given :specific heat capacity of water is 4186

J k g^{- 1} K^{- 1}

specific heat capacity of copper calorimeter is 385

J k g^{- 1} K^{- 1}

A refrigerator converts 100 g of water at $20^{o} C$ to ice at $- 10^{o} C$ in 73.5 min. Calculate the average rate of heat extraction in watt. The specific heat capacity of water is 4.2 J $g^{- 1} K^{- 1}$ , specific latent heat of ice is 336 J $g^{-} 1$ and the specific heat capacity of ice is 2.1 J $g^{- 1} K^{- 1}$ .

Join BYJU'S Learning Program

1.0 kg of water is contained in a 1.25 kW kettle. Calculate the time taken for the temperature of water to rise from 25∘C to its boiling point 100∘C. Specific heat capacity of water =4.2 J g−1K−1 .

Let the time taken is tHeat loss by kettle=heat gain water1.25×103×t=Q=mCΔTC is the specific heat capacity of watereg: C=42J/kg/kΔT=(100−25)℃1250×t=1×4200×(100−25)1250×t=4200×7550t=12600t=12605=252sec

1.0 kg of water is contained in a 1.25 kW kettle. Calculate the time taken for the temperature of water to rise from $25^{\circ} C$ to its boiling point $100^{\circ} C$ . Specific heat capacity of water = $4.2 J g^{- 1} K^{- 1}$ .