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Question

1.0 mL of KMnO4 solution reacts with 0.125 g Fe2+. If 1.0 mL KHC2O4.H2C2O4 solution reacts with 0.175 mL of same KMnO4 solution, 8.4 ml volume of 0.2MNaOH which will be used to neutralise 1.0 mL of tetroxalate solution (all the three protons in tetroxalate are titrable).

A
True
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B
False
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Solution

The correct option is A True
MnO4+5Fe2++8H+5Fe3++Mn2++4H2O
The molar mass of iron is 55.8 g/mol. 0.125 g of Fe(II) ions corresponds to 0.12555.8=0.00224 moles. They will react with 0.002245=0.000448 moles of KMnO4.
2MnO4+5H2C2O4+6H+2Mn2++10CO2+8H2O
0.000448 moles of KMnO4 will react with 0.000448×54=0.00056 moles of tetraoxalate.
0.00056 moles of tetraoxalate will be neutralized with 3×0.00056=0.00168 moles of NaOH.
Volume of 0.2 M NaOH solution required =0.001680.2=0.0084L=8.4mL

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