1.0 Molar solution of the complex salt, CrCl3.6H2O displays an osmotic pressure of 3 RT. 0.5 L of the same solution will yield (assume α=1) 'x' moles of AgCl the value of 'x' is
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Solution
π=iCRT;i=3=1+(n−1)α For the salt α=1, hence n = 3. [Cr(H2O)5Cl]Cl2.H2O+2AgNO3→[Cr(H2O)5Cl]2++2AgCl(s) 0.5 L of 1 M salt = 0.5×2=1.0 mole of AgCl