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Standard XII

Chemistry

Alpha Decay

1.0 g atom of...

Question

$1.0 g$ atom of an $α$ − emitting isotope $(t_{1 / 2} = 10 days)$ is sealed in a container. The volume of the gas accumulated in the container at STP after 10 days would be:

1.0 L

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44.8 L

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11.2 L

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22.4 L

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Solution

The correct option is C $11.2 L$
$X \to Y +_{2}^{4} H e$
t=0 $1$
t=10 $\frac{1}{2}$ $\frac{1}{2}$ $\frac{1}{2}$

$P V = n R T$
$1 \times V$ = $\frac{1}{2} \times 0.0821 \times 273$
$V = 11.2 L$

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1.0 g atom of an α − emitting isotope (t1/2=10 days) is sealed in a container. The volume of the gas accumulated in the container at STP after 10 days would be:

The correct option is C 11.2 L X→ Y + 42He t=0 1 t=10 12 12 12 PV=nRT 1×V = 12×0.0821×273 V=11.2 L

$1.0 g$ atom of an $α$ − emitting isotope $(t_{1 / 2} = 10 days)$ is sealed in a container. The volume of the gas accumulated in the container at STP after 10 days would be:

The correct option is C $11.2 L$
$X \to Y +_{2}^{4} H e$
t=0 $1$
t=10 $\frac{1}{2}$ $\frac{1}{2}$ $\frac{1}{2}$

$P V = n R T$
$1 \times V$ = $\frac{1}{2} \times 0.0821 \times 273$
$V = 11.2 L$