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Law of Reciprocal Proportions

1.08 gram of ...

Question

1.08 gram of $C u$ wire was allowed to react with nitric acid. The resulting solution was dried and ignited when 1.35 grams of copper oxide was obtained. In another experiment, 2.3 grams of copper oxide was heated in the presence of Hydrogen yielding 1.84 grams of copper. The data illustrates:

A

Law of multiple proportion

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B

Law of mass conservation

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C

Law of constant composition

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D

Law of reciprocal proportion

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Solution

The correct option is C Law of constant composition
Weight ratio of Cu : O in copper oxide 1 $= \frac{1.08}{0.27} = \frac{4}{1}$

Weight ratio of Cu : O in copper oxide 2 $= \frac{1.84}{2.3 - 1.84} = \frac{4}{1}$

The data illustrates the law of constant composition.

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