If |[ 1 0; 0 1 ]|=|[ x 0; 0 x ]|, then the value of xis

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Standard XII

Mathematics

Differentiation of a Determinant

If |[ 1 0; 0 ...

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The correct option is C
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f (x) = \frac{p + q^{\frac{1}{x}}}{r + s^{\frac{1}{x}}}, s < 1, q < 1, r \neq 0, f (0) = 1

, is left continuous at

x = 0

then

The solution for the equations $c_{1} x + b_{1} y + a_{1} = 0$ and $c_{2} x + b_{2} y + a_{2} = 0$ is

S1 : $x = \frac{(b_{1} a_{2} - b_{2} a_{1})}{(c_{1} b_{2} - c_{2} b_{1})}$

S2 : $y = \frac{(a_{2} c_{1} - a_{1} c_{2})}{(c_{2} b_{1} - c_{1} b_{2})}$

If $\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$ in the system of equations $a_{1} x + b_{1} y + c_{1} = 0$ and $a_{2} x + b_{2} y + c_{2} = 0$

S1 : The following is condition for inconsistent equations

S2 : There exists infinitely many solutions

S3 : The equations satisfying the condition are parallel

Which of the following statements are true ?

The solution for the equations $c_{1}$ x + $b_{1}$ y + $a_{1}$ = 0 and $c_{2}$ x + $b_{2}$ y + $a_{2}$ = 0 is

S1 : x = $\frac{(b_{1} a_{2} - b_{2} a_{1})}{(c_{1} b_{2} - c_{2} b_{1})}$

S2 : y = $\frac{(c_{1} a_{2} - c_{2} a_{1})}{(a_{1} b_{2} - a_{2} b_{1})}$

S1 : Logarithm of a number x is defined for all negative values of x.
S2 : Logarithm of 1 to the base x (where x>1) = 0

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The correct option is C ±1

The correct option is C
±1