Question

1, 1, 2, 2-Tetra bromoethane $\stackrel{Zn}{\to }A$ $\stackrel{redhottube}{\to }B$,

Then B is:

• A. Acetylene
• B. Ethylene
• C. Ethane
• D. Benzene

Answer 1

The correct option is D Benzene

$H-\stackrel{Br}{\stackrel{|}{\underset{Br}{\underset{|}{C}}}}-\stackrel{Br}{\stackrel{|}{\underset{Br}{\underset{|}{C}}}}-H\underset{△}{\overset{Zn}{\to }}H-C\underset{\left(A\right)}{\equiv }C-H\stackrel{redhottube}{\to }{C}_6{H}_6$

Option D is correct.