1, 1, 8, 4, 27, 9, ......

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Solution

The correct option is B 64
There are 2 series in the given series
Series 1: 1,8,27,..
Series 2: 1,4,9,
The next number belongs to Series 1 that will be a cube of 4 . i.e. 64
Answer is Option B

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Similar questions

1, 1, 1, 2, 4, 8, 3, 9, 27, 4, 16, 32

1, - 3 / 2, 9 / 4, - 27 / 8, . . . . .

n L t \to \infty [\frac{1}{1 + n^{3}} + \frac{4}{8 + n^{3}} + \frac{9}{27 + n^{3}} + \dots . + \frac{1}{2 n}] =

{lim}_{n \to \infty} \frac{1 + 1 + 4 + 8 + 9 + 27 + 16 + 64 + . . .}{(1 + 2 + 3 + 4 + 5 + . . .)^{2}} =

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