$(1)$ $1 - b u t e n e$ $(2)$ $b u t a n e$
$(3)$ $1 - b u t y n e$ $(4)$ $N H_{3}$
Rank the above compounds with rescept to increasing acidity:

4 < 3 < 1 < 2

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2 < 1 < 4 < 3

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2 < 1 < 3 < 4

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3 < 1 < 2 < 4

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Solution

The correct option is B 2 < 1 < 4 < 3
Increasing acidity order is:

$b u t a n e < 1 - b u t e n e < N H_{3} < 1 - b u t y n e$

1-butyne is more acidic than $N H_{3}$ , $N H_{3}$ is more acidic than 1-butene, 1-butene is more acidic than butane.

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Similar questions

Q. The D in the given reaction is:

1) But-2-ene 2)1-butyne 3)Butane 4)Butanal

Simplify:

$(i) {{(\frac{1}{3})}^{- 3} - {(\frac{1}{2})}^{- 3}} \div {(\frac{1}{4})}^{- 3} (i i) (3^{2} - 2^{2}) \times {(\frac{2}{3})}^{- 3} (i i i) {(\frac{1}{2}) \times (- 4)^{- 1}}^{- 1} (i v) {[{{(\frac{- 1}{4})}^{2}}^{- 2}]}^{- 1} (v) {{(\frac{2}{3})}^{2}}^{3} \times {(\frac{1}{3})}^{- 4} \times 3^{- 1} \times 6^{- 1}$

Evaluate :

$(i) (3^{- 1} \times 9^{- 1}) \div 3^{- 2} (i i) (3^{- 1} \times 4^{- 1}) \div 6^{- 1} (i i i) (2^{- 1} + 3^{- 1})^{3} (i v) (3^{- 1} \div 4^{- 1})^{2} (v) (2^{2} + 3^{2}) \times {(\frac{1}{2})}^{2} (v i) (5^{2} - 3^{2}) \times {(\frac{2}{3})}^{- 3} (v i i) [{(\frac{1}{4})}^{- 3} - {(\frac{1}{3})}^{- 3}] \div {(\frac{1}{6})}^{- 3} (v i i i) {[{(- \frac{3}{4})}^{- 2}]}^{2} (i x) {{(\frac{3}{5})}^{- 2}}^{- 2} (x) (5^{- 1} \times 3^{- 1}) \div 6^{- 1}$

1 + 2 + 3 + 4 + . . . . . + n = ?

1 + 2 + 3 + 4 + . . . . . + (n - 1) = ?

1 + 1 + 1 + 1 + . . . . . + n = ?

1 + 1 + 1 + 1 + . . . . . . + (n - 1) = ?

1^{2} + 2^{2} + 3^{2} + 4^{2} + . . . . + n^{2} = ?

1^{2} + 2^{2} + 3^{2} + 4^{2} + . . . . + {(n - 1)}^{2} = ?

Find the value of.

(i) (3⁰ + 4⁻¹) × 2² (ii) (2⁻¹ × 4⁻¹) ÷2⁻²

(iii) (iv) (3⁻¹ + 4⁻¹ + 5⁻¹)⁰

(v)

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(1) 1−butene (2) butane(3) 1−butyne (4) NH3Rank the above compounds with rescept to increasing acidity:

The correct option is B 2 < 1 < 4 < 3Increasing acidity order is:butane<1−butene<NH3<1−butyne1-butyne is more acidic than NH3, NH3 is more acidic than 1-butene, 1-butene is more acidic than butane.

$(1)$ $1 - b u t e n e$ $(2)$ $b u t a n e$
$(3)$ $1 - b u t y n e$ $(4)$ $N H_{3}$
Rank the above compounds with rescept to increasing acidity:

The correct option is B 2 < 1 < 4 < 3
Increasing acidity order is:

$b u t a n e < 1 - b u t e n e < N H_{3} < 1 - b u t y n e$

1-butyne is more acidic than $N H_{3}$ , $N H_{3}$ is more acidic than 1-butene, 1-butene is more acidic than butane.