Question

$1.12Litre$ dry chlorine gas at STP was passed over a heated metal then $5.56$ g of chloride of the metal was formed. What is the equivalent weight of the metal?

Answer 1

At STP, $1$ mole= $22.4$ $L$

$\therefore$ $1.12$ $L$= $\frac{1.12}{22.4}$ moles= $0.05$ moles

$\therefore$ Moles of dry chlorine gas at STP= $0.05$ moles

Let the equivalent weight of metal be $E$.

$\therefore$ $0.05=\frac{5.56}{E+35.5}$

$\therefore$ $E+35.5=111.2$

$\therefore$ $E=75.7$ $grams$
Therefore, equivalent weight of metal is $75.7$ $grams$.