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Question

1.17 g of an impure sample of oxalic acid was dissolved and made up to 200 mL with water. 10 mL of this solution in acid medium required 8.5 mL of a solution of potassium permanganate containing 3.16 g per litre of oxidation. Calculate the percentage purity of oxalic acid.

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Solution

During the redox reaction
we have,
no. of gram equivalent of oxidising agent = gram equivalent weight of reducing agent
or N1V1=N2V2
N= weightweightequivalentweightvolume

let pure form of oxalic acid weigh = x
so we have,
x10001063200= 3.168.531.6

x= 1.071 g

percentage purity = pureformimpureform100
percentage purity = 91.53

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