You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Chemistry

Volume of Gases and Number of Moles

1.19 g mixtur...

Question

$1.19$ g mixture of Cu, Zn and Al contain $50$ % copper by weight and $3 \times 10^{21}$ atoms of zinc, find gram atoms of aluminium in given mixture? (Atomic mass of $A l = 27; C u = 63.55, Z n = 65.0$ ) [ $N_{A} = 6 \times 10^{23}$ ]

0.001

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.27

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.01

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.027

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D 0.01
Weight of Cu in the mixture $= 1.19 \times \frac{50}{100}$ $= 0.595 g$
$W_{Z n} = \frac{3 \times 10^{21}}{6 \times 10^{23}} \times 65 = 0.325 g$
So, $W_{A l} = 1.19 - (0.595 + 0.325) g = 0.27 g$
Gram atom or mole of $A l = \frac{0.27}{27} = 0.01$

Suggest Corrections

Similar questions

L i

K

C a

N a

M g

A l

Z n

F e

P b

C u

H g

A g

I

. The reaction

Z n (s) + C u {({N O}_{3})}_{2} (a q) \to C u (s) + Z n {({N O}_{3})}_{2} (a q)

will occur.

I I

. Zinc and copper are both transition metals.

Q. When

Z n

dust is added to sufficiently large volume of aqueous solution of copper sulphate.

3.175

g of copper metal and

20

J of heat is evolved. The

Δ H

for the reaction is:

Z n (s) + C u S O_{4} (a q) ⟶ Z n S O_{4} (a q) + C u (s)

(Atomic weight of

Z n = 65.3

, atomic weight of

C u = 63.5

)

Q. In an experiment,

6.67

g of

A l C l_{3}

was produced and

0.54

g of

A l

remained unreacted. How many gram atoms of

A l

and

C l_{2}

were taken originally? (Given that atomic weight of

A l

27

g and of

C l

35.5

g.)

Q. Find the number of oxygen atom present in

0.051 g

of aluminium oxide.
(Given: atomic mass of

A l = 27 u

)

Q. Copper crystallizes in face centred cubic lattice and has dencity of

8.930

c m^{-} 3

298

K. Calculate the radius of copper atom.(At mass of Cu=

63.55

u,N

_{A}

6.02 \times 1023 m o l^{-} 1)

Join BYJU'S Learning Program

1.19 g mixture of Cu, Zn and Al contain 50% copper by weight and 3×1021 atoms of zinc, find gram atoms of aluminium in given mixture? (Atomic mass of Al=27;Cu=63.55,Zn=65.0) [NA=6×1023]

The correct option is D 0.01Weight of Cu in the mixture =1.19×50100 =0.595gWZn=3×10216×1023×65=0.325gSo, WAl=1.19−(0.595+0.325)g=0.27gGram atom or mole of Al=0.2727=0.01

$1.19$ g mixture of Cu, Zn and Al contain $50$ % copper by weight and $3 \times 10^{21}$ atoms of zinc, find gram atoms of aluminium in given mixture? (Atomic mass of $A l = 27; C u = 63.55, Z n = 65.0$ ) [ $N_{A} = 6 \times 10^{23}$ ]

The correct option is D 0.01
Weight of Cu in the mixture $= 1.19 \times \frac{50}{100}$ $= 0.595 g$
$W_{Z n} = \frac{3 \times 10^{21}}{6 \times 10^{23}} \times 65 = 0.325 g$
So, $W_{A l} = 1.19 - (0.595 + 0.325) g = 0.27 g$
Gram atom or mole of $A l = \frac{0.27}{27} = 0.01$