The AP corresponding to the given series is 1, 2, 3,..., 27.
Sum of n natural numbers is given by Sn = n(n+1)2.
⇒S27=27(27+1)2 =27×282 =27×14 =378
Solve:
[[5×{(−3)×(−4)}]÷{27 + (−14−3)}][[3×{(−4)×(−5)}]÷{27+(−13−4)}] +[{27×(−2)}÷(−3−3)] + [{27×(−2)}÷(−3−3)] +[{(−3)×(−3)×5}÷(−3)]]
[3×[(-5)×(-4)]÷[27+(-13-4)]+[(27×(-2)]÷(-3-3)+[(-3)×(-3)×(-5)÷(-3)
Can you explain clearly