(1)^any number = 1 ( 1)^odd number = 1 ( 1)^even number = +1 (1)^ a = 1/1^a=+1 ∴ nbsp;( 1)^2017 gives 1 which is less than nbsp;1. ...

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Zero as an Exponent

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Question

$1^{2018}$ >

1^{- 2018}

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1^{2017}

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(- 1)^{2017}

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(- 1)^{2018}

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Solution

The correct option is C $(- 1)^{2017}$
${(1)}^{a n y n u m b e r} = 1$
${(- 1)}^{o d d n u m b e r} = - 1$
${(- 1)}^{e v e n n u m b e r} = + 1$
${(1)}^{- a} = \frac{1}{1^{a}} = + 1$
$∴$ $(- 1)^{2017}$ gives -1 which is less than 1.

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