1.225 g sample of KClO3 was heated under such conditions that a part of it decomposed according to the equations given below. If the amount of O2 evolved was 168 mL at STP, calculate the weight of KClO4.
(Molar mass of KClO3=122.5 g mol−1,KClO4=138.5g mol−1)KClO3→KCl+O2KClO3→KClO4+KCl