Question

1.24 gm P is present in 2.2 gm of

• A. P₄S₃
• B. P₂S₂
• C. PS₂
• D. P₂S₄

Answer 1

The correct option is A

P₄S₃

In $P_4$$S_3$

$\because$ $\frac{31\times 4}{124}$gm P is present in $220gm$ $P_4$$S_3$

$\therefore 1.24gm$ P present =$\frac{220}{124}\times 1.24$ = $2.2gm$