Question

1.25 g of a solid dibasic acid is completely neutralised by 25 ml of 0.25 molar $Ba(OH{)}_2$ solution. Molecular mass of the acid is

• A. 100
• B. 150
• C. 120
• D. 200

Answer 1

The correct option is D 200

Molarity= $\frac{W\left(gm\right)\times 1000}{V\left(ml\right)\times molecularweight}$
$0.25=\frac{1.25\times 1000}{25\times molecularweight}$
$\therefore$ Molecular weight $=\frac{1.25\times 1000}{0.25\times 25}=200$.