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Types of Redox Reactions

1.26 g dehydr...

Question

$1.26 g$ dehydrated oxalic acid is dissolved in $250 m l$ . $25 m l$ of this solution is treated with $0.5 M N a O H$ solution.
Find the volume of $N a O H$ used.

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Solution

Molarity of dehydrated oxalic acid $(M_{1})$ $= \frac{M o l e s}{V o l u m e (i n L)}$
$= \frac{1.26 g / 90 g / m o l}{0.25}$
$M_{1} = 0.056 M$
$V_{1} = 0.25 L$
$M_{2} = 0.05 M$
Now, $M_{1} V_{1} = M_{2} V_{2}$
$∴ V_{2} = \frac{M_{1} V_{1}}{M_{2}} = \frac{0.056 \times 0.25}{0.05} = 0.28 L$
$∴$ Volume of $N a O H$ used $(V_{2}) = 0.28 L = 280 m L$

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