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Fundamental and Derived Units

1.2g of Mg(at...

Question

1.2g of Mg(at mass 24) will produce MgO equal to

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Solution

$T h e r e q u i r e d e q u a t i o n i s 2 M g + O_{2} \to 2 M g O 2 \times 24 2 (24 + 16) = 48 g = 80 g 48 g o f m a g n e s i u m p r o d u c e s 80 g o f M g O . 1.2 g o f m a g n e s i u m p r o d u c e s = \frac{80}{48} \times 1.2 = 2 g o f M g O$

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1.5 mol of $O_{2}$ combines with $M g$ to form the oxide $M g O$ . The mass of $M g$ (at. mass 24) that has combined is:

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