$(1^{3} + 2^{3} + 3^{3} + 4^{3})^{- 3 / 2}$ =

10^{- 3}

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10^{- 2}

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10^{- 4}

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10^{- 1}

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Solution

The correct option is A $10^{- 3}$
$(1^{3} + 2^{3} + 3^{3} + 4^{3})^{- 3 / 2}$ $\Rightarrow$ $(1 + 8 + 27 + 64)^{- 3 / 2}$

$\Rightarrow$ $(100)^{- 3 / 2}$

$\Rightarrow$ $(\sqrt{100})^{- 3}$

$\Rightarrow$ $10^{- 3}$

$∴$ $(1^{3} + 2^{3} + 3^{3} + 4^{3})^{- 3 / 2} = 10^{- 3}$

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Similar questions

Evaluate $(1^{3} + 2^{3} + 3^{3} + 4^{3})^{\frac{- 3}{2}} .$

Evaluate:- $(1^{3} + 2^{3} + 3^{3} + 4^{3})^{\frac{- 3}{2}}$

1^{3} + 2^{3} + \frac{3^{3}}{⌊ 2} + \frac{4^{3}}{⌊ 3} + \frac{5^{3}}{⌊ 4} + . . . .

1 + \frac{2^{3}}{2!} + \frac{3^{3}}{3!} + \frac{4^{3}}{4!} + . . . . . . \infty

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