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Quantitative Aptitude

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13+23+……+93=2...

Question

$1^{3} + 2^{3} + . . . . . . . + 9^{3} = 2025, t h e n t h e v a l u e o f {0.11}^{3} + {0.22}^{3} + . . . . . . + {0.99}^{3} i s c l o s e t o$

A

0.2695

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B

0.3695

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C

2.695

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D

3.695

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Solution

The correct option is C
2.695

${0.11}^{3} + {0.22}^{3} + . . . . . . . . . + {0.99}^{3} = {0.11}^{3} \times (1^{3} + 2^{3} . . . . . . . . + 9^{3}) = 2.695$

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