1+3 = 4
1+3+5 = 9
then find sum 1+3+5+.... (upto 8 terms )

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Solution

The correct option is D 64
1+3 = 4 = $2^{2}$ ---- ( 2 terms; 2 $^{2}$ =4)
1+3+5 = 9 = $3^{2}$ ----- ---- ( 3 terms; 3 $^{2}$ =9)
1+3+5+.... (upto 8 terms ) = $8^{2}$ = 64

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