1, 3, 4, 8, 15, 27, ?

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Solution

The correct option is C 50
The sum of any three consecutive terms of the series gives the next term.
So, missing number = 8 + 15 + 27 = 50.

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Similar questions

Simplify:

(1) 7²⁸*7¹⁵*1/7¹³

(2) (1/3)⁴*(-27/4)²*(-8/3)²

1, 3, 4, 8, 15, 27, ?

(\frac{- 9}{7} \times \frac{- 1}{3}) + (\frac{15}{8} \times \frac{- 4}{5}) - (\frac{27}{14} \times \frac{2}{9})

1, - 3 / 2, 9 / 4, - 27 / 8, . . . . .

27 - {13 + 4 - (8 + 4 - ¯ ¯¯¯¯¯¯¯¯¯¯ ¯ 1 + 3)}

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