You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sum of the First n Odd Natural Numbers Is Equal to n Squared

1+3+5+…+51=?

Question

1 + 3 + 5 +...+ 51 = ?

576

No worries! We‘ve got your back. Try BYJU‘S free classes today!

676

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

276

No worries! We‘ve got your back. Try BYJU‘S free classes today!

476

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 676
Remainder obtained after dividing 51 by 2 = 25.
Therefore number of terms, n = 25 + 1 = 26.
$1 + 3 + 5 + . . . + 51 = n^{2} = 26^{2} = 676$

Suggest Corrections

Similar questions

5 \frac{1}{3}

5 \frac{2}{3}

\div

\frac{1}{3}

\div

x + 3

\frac{1}{5}

\div

1 \frac{1}{5}

= 7

Simplify:

(i) $\frac{\sqrt{5} + \sqrt{3}}{\sqrt{5} - \sqrt{3}} + \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} + \sqrt{3}}$

(ii) $\frac{1}{2 + \sqrt{3}} + \frac{2}{\sqrt{5} - \sqrt{3}} + \frac{1}{2 - \sqrt{5}}$

(iii) $\frac{2}{\sqrt{5} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{2}} - \frac{3}{\sqrt{5} + \sqrt{2}}$

Solve: $5 \frac{1}{3} - [2 \frac{1}{3} \div {\frac{3}{4} - \frac{1}{2} \times (\frac{7}{10} - \frac{3}{5})}]$

Question 51

Solve the following:

$\frac{2 x - 3}{4 x + 5} = \frac{1}{3}$

1 + 3 + 5 + . . . . . + 51

1

51

Join BYJU'S Learning Program