Question

1 + 3 + 5 + 7 + 9 + 11 =

• A. $4^2$
• B. $8^2$
• C. $2^2$
• D. $6^2$

Answer 1

The correct option is D $6^2$

Sum of first 'n' odd natural numbers will be equal to $n^2$.

Example:
Sum of first 2 odd natural numbers =1 + 3 = $2^2$ = 4
Sum of first 3 odd natural numbers =1 + 3 + 5 = $3^2$ = 9

$\therefore$ Sum of first 6 odd natural numbers = 1 + 3 + 5 + 7 + 9 + 11 = $6^2$ = 36