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Nth Term of a GP

1, 3, 7, 15, ...

Question

$1, 3, 7, 15, 31, . . . . . . .$
Find next term of the series

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Solution

Here $t_{n} = 2^{n} - 1$
$t_{6} = 2^{6} - 1 = 63$
$t_{7} = 2^{7} - 1 = 127$
$t_{8} = 2^{8} - 1 = 255$
$t_{9} = 2^{9} - 1 = 511$

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