1, 3-Butadiene with bromine in molar ratio generates predominantly:

1,1 dibromo-2- butene

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1,4 dibromo-2- butene

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1,2 dibromo-2-butene

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1,3 dibromo-2-butene

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Solution

The correct option is B 1,4 dibromo-2- butene
$C H_{2} = C H - C H = C H_{2} + B r_{2} \to B r C H_{2} C H B r C H = C H_{2} + B r C H_{2} C H = C H C H_{2} B r$
3,4-dibromo-1-butene 1,4-dibromo-2-butene

1,4-dibromo-2-butene is more predominant due to a resonance structure stabilizes the intermediate formed during the reaction.

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