( 1)^ 3 = 1/( 1)^3 ( 1)^3 = ( 1)×( 1)×( 1) = 1×( 1) = 1 So 1/( 1)^3= 1/ 1 = 1 So ( 1)^ 3 = 1 ...

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(a^m)^n=a^mn and a^0 = 1

-1-3 is

Question

$(- 1)^{- 3}$ is

__

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Solution

$(- 1)^{- 3}$ = $\frac{1}{(- 1)^{3}}$
$(- 1)^{3}$ = (-1)×(-1)×(-1)
= 1×(-1)
= -1
So
$\frac{1}{(- 1)^{3}}$ = $\frac{1}{- 1}$ = -1
So $(- 1)^{- 3}$ = -1

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