( 1)^ 3 =1/( 1)^3 Since, ( 1)^3 = ( 1) × ( 1) × ( 1) = 1/ 1 × 1 × 1 = 1/ 1 = 1 ...

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(a^m)^n=a^mn and a^0 = 1

-1-3 is:

Question

$(- 1)^{- 3}$ is:
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Solution

$(- 1)^{- 3}$ = $\frac{1}{(- 1)^{3}}$
Since, $(- 1)^{3}$ = (-1) $\times$ (-1) $\times$ (-1)
= $\frac{1}{- 1 \times - 1 \times - 1}$
= $\frac{1}{- 1}$
= -1

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