$1.3 x - 0.7 y = 0.9$ and $0.7 x - 1.3 y = 3.1$ . There fore $x + y =$ _____

\frac{- 11}{3}

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Solution

The correct option is A $\frac{- 11}{3}$
$1.3 x - 0.7 y = 0.9$ $- (1)$
$0.7 x - 1.3 y = 3.1$ $- (2)$
$(1) - (2)$
$0.6 x + 0.6 y = - 2.2$
$x + y = \frac{- 22}{6} = \frac{- 11}{3}$

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Similar questions

0.9 x + 0.5 y = 6;

0.7 x + 0.7 y = 5 \cdot 6

0.9 x + 0.5 y = 6; 0.7 x + 0.7 y = 5.6

x - y = 0.9

\frac{11}{x + y} = 2

x - y = 0.9

11 {(x + y)}^{- 1} = 2

x : 0.7 x + 2 (x - 3) = 0.2 x + 3

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