Question

1) 3x/2-5y/3+2=0

X/3+y/2=13/6

Solved it by elimination of substitution

2) X/6+y/15=4

X/3-y/12=19/4

Solved it by elimination of substitution

Answer 1

(1)

3x /2 -5y/3 = -2 ----1

x/3 + y/2 = 13/6 ---2

take the lcm of 6 in 1 and2

therefore, 9x-10y=-12 -----3

from this x= -12+10y/9---5

and 2x+3y =13 -----4

putting 5 in 4

therefore, y=3

and from 5
x= 2 {byputting thevalue of y in it}