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Question

(1) 42 + 24 − 32

(2) 33 − 22 + 20

(3) 53 − 22 + 40

(4) 61 + 50 − 41

(5) (−2)2 + 12 − 22


Solution

(1) 42 + 24 − 32 =4 × 4 + 2 × 2 × 2 × 2 − 3 × 3 = 16 + 16 − 9 = 23

(2) 33 − 22 + 20 = 3 × 3 × 3 − 2 × 2 + 1 = 27 − 4 +1= 24

(3) 53 − 22 + 40 = 5 × 5 × 5 − 2 × 2 + 1 = 125 − 4 +1= 122

(4) 61 + 50 − 41 = 6 + 1 − 4 = 3

(5) (−2)2 + 12 − 22 = (−2) × (−2) + 1 × 1 − 2 × 2 = 4 + 1 − 4 = 1


Mathematics
Mathematics Semester I
Standard VII

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