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Standard XII

Chemistry

Stoichiometry

1.44g of tita...

Question

1.44g of titanium(Ti) reacted with an excess of $O_{2}$ and produced X gm of a non-stoichiometric compound ${T i}_{1.44} O_{1}$ . The value of X is:

1.44

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1.77

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None of these

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Solution

The correct option is A 1.77
Moles of $T i$ in Reactant $=$ moles of $T i$ in product
$\frac{1.44}{48} = \frac{1.44 x}{(1.44 \times 48) + 16}$
$0.03 = \frac{1.44 x}{85.12}$
$0.03 \times 85.12 = 144 x$
$x = \frac{2.5536}{1.44}$
$= 1.77$
Hence, the correct option is $C$

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1.44g of titanium(Ti) reacted with an excess of O2 and produced X gm of a non-stoichiometric compound Ti1.44O1. The value of X is:

The correct option is A 1.77Moles of Ti in Reactant = moles of Ti in product1.4448=1.44x(1.44×48)+160.03=1.44x85.120.03×85.12=144xx=2.55361.44=1.77Hence, the correct option is C

1.44g of titanium(Ti) reacted with an excess of $O_{2}$ and produced X gm of a non-stoichiometric compound ${T i}_{1.44} O_{1}$ . The value of X is:

The correct option is A 1.77
Moles of $T i$ in Reactant $=$ moles of $T i$ in product
$\frac{1.44}{48} = \frac{1.44 x}{(1.44 \times 48) + 16}$
$0.03 = \frac{1.44 x}{85.12}$
$0.03 \times 85.12 = 144 x$
$x = \frac{2.5536}{1.44}$
$= 1.77$
Hence, the correct option is $C$